ANSWER: 69.146% of all applicants will complete application in 11 minutes.
NORMAL DISTRIBUTION, STANDARDIZED VARIABLE z, PROBABILITY “LOOK-UP”
z = (x – μ)/σ STANDARDIZED VARIABLE FOR NORMAL x = INDEPENDENT VARIABLE [9] μ = POPULATION MEAN [9] σ = POPULATION STANDARD DEVIATION [4]
z = (11- 9)/4 = 0.5
NORMAL DISTRIBUTION (cumulative), PROBABILITY “LOOK-UP” z P( Z <= z ) 0.5 0.69146 (69.146%)
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ANSWER: 69.146% of all applicants will complete application in 11 minutes.
NORMAL DISTRIBUTION, STANDARDIZED VARIABLE z, PROBABILITY “LOOK-UP”
z = (x – μ)/σ STANDARDIZED VARIABLE FOR NORMAL
x = INDEPENDENT VARIABLE [9]
μ = POPULATION MEAN [9]
σ = POPULATION STANDARD DEVIATION [4]
z = (11- 9)/4 = 0.5
NORMAL DISTRIBUTION (cumulative), PROBABILITY “LOOK-UP”
z P( Z <= z )
0.5 0.69146 (69.146%)